Question

. Durgesh has three boxes of fruits. Box I
contains 1/2 kg more than Box III and
Box III contains 2 1/2 kg less than Box II.
If the total weight of the boxes is 146 1/2 kg. find the weight of each box.
​

Answer 1

$\huge{\mathcal{\blue{\underline{\underline{\pink{HeY!!}}}}}}$

${\small{\red{\boxed{60.425\: kg, \:\:31.33\: kg\:\: and\:\: 30.83 \:kg \:\:respectively. }}}}$

$<marquee>EXPLANATION</marquee>$

Given:-

• Durgesh has 3 boxes of fruit. {Box ।, ।।, ।।।}

• Box | contains 1/2kg more than box |||.

• Box ||| contains 2 1/2 kg less than Box ||.

• Total weight = 146 1/2 kg.

Let the weight of box || be x kg.

So ,

• Box ||| contains (x - 2 1/2) kg fruits.

• And,Box | contains 1/2+(x-2 1/2) kg fruits.

Now,

According To the Question,

x + {1/2 + (× - 2 1/2)} + {(× - 2 1/2)} = 146 1/2.

=》 x+1/2+x-5/2+x-5/2 = 293/2

{Converting into improper fraction}

=》 3x+1/2-10/2 = 239/2.

=》 3x-9/2 = 239/2.

=》 3x = 239/2+9/2.

=》 3x = 248/2.

=》 3x = 124.

=》 x = 124/3.

=》 x = 31.33 [Approx]

So weight of box || is 31.33 kg,

Weight of box |||

= 31.33 - 5/2 = 61.66/2 = 30.83 kg

Weight of box |

= 1/2+30.83 = 60.425 kg.

Therefore weight of box |, || and ||| is 60.425 kg, 31.33 kg and 30.83 kg respectively.

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$<marquee>THANKS</marquee>$