Question

Duride 56 in four parts
are in AP Such that the
ratio of product of their
extremes to the product
of means is 5:6. Find the
four parts.​

Answer 1

Answer:

Answer:Let the four parts that are in AP be a-3d,a+d, a+3d

a-3d+a-d +a+d+a+3d=36

4a=56

a=14

ATQ

(a-3d)(a+3d)=5÷ ( a-d) (a+d)=6

a^2-9d^2÷a^2-d^2=5÷6

6(196-9d^2)=5(196-d^2)

1176-54d^2=980-5d^2

49d^2=196

d=+-2

four part 8,12 d=2 and 20,16,12if d=-2

Answer 2

Step-by-step explanation:

hope you will satisfy...