Question

during a campaign an army loses 1/10 of it's members in battle and 1/5 by sickness; what fraction survive
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Answer 1

Number of people lost in campaign= 1/10——————->(1)

Since 10 is a divisible of 5, we can multiply the denominator of the members lost by sickness to make it 10.

Multiplying numerator and denominator by 2, we get=>

1/5 X 2= 2/10———————>(2)


Now adding the 2 eqs, we get 1/10+2/10= 3/10.

Therefore, total number of people lost on war is 3/10 or 30%.

Remaining people are:-

1 - 3/10
=> 10/10 - 3/10
=> 7/10

Hence, 7/10 or 70% of army members survived