During a campaign an army loses 1/10 of its members in battle and 1/5 by sickness what fraction survives?
Answers
Answered by
15
Answer:
total part in fatalities and sickness = 1/10 + 1/5 = 1/10 +2/10=3/10
Surviving = 1-3/10 = 10/10 -3/10 =7/10
So 7/10 of the army survives.
BRAINLIEST plz/.
Step-by-step explanation:
Answered by
21
Answer:7/10
Step-by-step explanation
Let total fraction of army be 10/10
Now, 1/10 are losed and 1/5 are losed by sickness
Let, the fraction of army left be x+1/5+1/10=10/10
=>x=10/10-3/10
=>x=7/10
Similar questions