Question

During a film, Gavin ate 2 1/3 handfuls of snack mix, and Aisha ate 2/3 of a handful. How much more did Gavin eat?

Answer 1

Given :

• Gavin ate 2 1 / 3 handful of snack mix

• Aisha ate 2 / 3 handful of snack mix

To find :

• How much more did Gavin eat ?

According to the question :

Gavin = 2 1 / 3

Aisha = 2 / 3

We are making ' 2 1 / 3 ' - mixed fraction, as Improper fraction,

Gavin = 2 1 / 3

⟹ ( 3 × 2 + 1 ) / 3

⟹ 7 / 3

∴ Gavin = 7 / 3 & Aisha = 2 / 3

Gavin - Aisha = The more Gavin get

⟹ 7 / 3 - 2 / 3

⟹ 7 - 2 / 3

⟹ 5 / 3

Gavin will get 5 / 3 handful of snack mix.

So Its Done !!

Answer 2

Answer:

Gavin ate $\frac{5}{3}$ portion more than Aisha.

Step-by-step explanation:

Given the portion ate by Gavin is $2 \frac{1}{3}$

The portion ate by Aisha $=\frac{2}{3}$

Converting the given mixed fraction into improper fraction,

$2 \frac{1}{3}= \frac{2\times 3+1}{3}=\frac{7}{3}$

The difference in the portions consumed by Gavin and Aisha is

$\frac{7}{3}-\frac{2}{3}$

As they have common denominator,

$\frac{7-2}{3}=\frac{5}{3}$

Therefore, Gavin ate $\frac{5}{3}$ portion more than Aisha.