Physics, asked by balakrishagaddam, 10 months ago

During a negative beta decay
(A) An atomic electron is ejected
(B) An electron which is already present within the nucleus is ejected
(C) A neutron in the nucleus decays emitting electrons
(D) A part of the binding energy is converted into electron

Answers

Answered by aniketgope41
1

Answer:

Negative β decay is expressed by the equation

n→p+e−+v.

So, a neutron decays into a proton and a negative beta particle (i.e electron) along with a anti-neutrino are emitted.

Answered by thamilkumaran65
1

Answer: option c

Explanation:*****************short version ****************

In beta decay

Neutron ----------> electron + proton + antineutrino

There goes the answer....option c

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