Question

During a physics practical at a lab, a 250g tetherball was tied to a pole with a 75cm string.
Calculate the tension force in the spring if the ball makes 10 horizontal revolution in 5 seconds.

Answer 1

Answer:

The tension in the string is = 0.296N

Explanation:

We first calculate the circumference of the circular motion :

Circumference = 22/7 × d

D = diameter

Diameter = 2 × 75 = 150 cm

In meters = 150/100 = 1.5 meters

Circumference = 3.142 × 1.5 = 4.713 meters.

In one revolution the ball covers 4.713 meters.

In 10 revolutions it covers = 4.713 × 10 = 47.13 meters.

The linear velocity is = 47.13/5 = 0.9426 m/s

Centripetal acceleration = m v²/r

V = the linear velocity

M = mass of the ball

r = radius of the circular path.

r = 75/100 = 0.75 m

M = 250/1000 = 0.25kg

V = 0.9426

Substituting we have :

0.25 × 0.9426² / 0.75

= 0.296 N

This is the Tension in the string.