Question

During a projectile motion, if the maximum height equals the horizontal range, then the angle of projection is what

Answer 1

Heya....!!!

This is the required answer

Angle will be approximately 76°

Answer 2

Horizontal range = u²sin2 Φ/g

Maximum height = u²sin²Φ/2g

now, ATQ
u²Sin 2Φ/g = u²sin²Φ/2g
2sin 2Φ = sin²Φ
4sinΦ cosΦ = sin²Φ
sinΦ/cosΦ = tanΦ = 4
Φ = tan-¹(4)

here is correct answer