during a storm a tree broke at a point but did not separate. Its top touched the ground at a distance 3.6 m from its base. If its point broke at a height 1.5 m from the ground, what was the total height of the tree before it broke
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Nice question
Solution-
Here BC is the foot of the tree .
Height of the tree = BD =?
In right angled ∆ ABC,
By Pythagoras theorem,
AC^2 =AB ^2+ BC ^2
AB ^2= BC ^ 2- AC^2
= ( 3.6) ^2 - (1.5) ^2
=12.96-2.25
=10.71
AB = 3.27
Height of the tree = AB+AC
= 3.27+1.5
= 4.77 m
The height of the tree is 4.77 m
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