. During a stunt, a cyclist (considered to
be a particle) is undertaking horizontal
circles inside a a cylindrical well of
radius 6.05 m. If the necessary friction
coefficient is 0.5, how much minimum
speed should the stunt artist maintain?
Mass of the artist is 50 kg. If she/he
increases the speed by 20%, how much
will the force of friction be?
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Answer:
Explanation:rictional force = f = mg
Centripetal Force = Contact force = N = mv² / r
μ = f / N
= mg / (mv^2 / r)
= rg / v²
= (5 × 10) / (5√5)²
= 50 / 125
= 0.4
Minimum coefficient of friction between the tyres and wall of the well must be 0.4.
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