During a stunt a cyclist ( considic to a particle) is undertaking horizontal circle inside a cyclindrical eel of radius is 6.05 if the necessary friction coefficient is 0.5 how much minimum speed should the stunt artist maintain ? Mass of the artist is 50kg if she /he increase the speed by 20% how much will be force of friction be,?
Ans= 11 m/s , fs= mg = 500 N
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Explanation:
Given During a stunt a cyclist (considered to a particle) is undertaking horizontal circle inside a cylindrical well of radius is 6.05 if the necessary friction coefficient is 0.5 how much minimum speed should the stunt artist maintain? Mass of the artist is 50 kg if she /he increase the speed by 20% how much will be force of friction be
- Given cylindrical well of radius r = 6.05 m
- Friction coefficient μ = 0.5
- Mass of the artist m = 50 kg
- So minimum speed or velocity to be maintained will be
- V = √rg / μ
- = √6.05 x 10 / 0.5 (g = 10 m/s^2)
- V = √121 m^2 / s^2
- Or V = 11 m / s
- Now force of friction depends on weight.
- Therefore f = fs = mg
- = 50 x 10
- Or f = 500 N
Reference link will be
https://brainly.in/question/16875538
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