During a tennis match, a player hits the ball reaching a speed of 58 m/s. What is the average force exerted on the 0.057-kg tennis ball by the player, assuming that the ball’s speed just after impact is 58 m/s and that the initial horizontal component of the velocity before impact is negligible and that the ball remained in contact with the racquet for 5.0 ms (milliseconds)? (With explaination please)
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Answer:
idk im sorry
Explanation:
im sorry
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661.2 N is the average force exerted on the 0.057-kg tennis ball by the player
Explanation:
F = m dv/dt
m = 0.057 kg
dv = 58 m/s
dt = 5 ms = 5 * 10⁻³ s
F = 0.057 * (58/ 5 * 10⁻³)
=> F = 57 * 58 / 5
=> F = 661.2 N
or v = u + at
=> 58 = 0 + a (5 * 10⁻³)
=> a = 58/ (5 * 10⁻³)
F = ma = 0.057 * (58/ 5 * 10⁻³) = 661.2 N
average force exerted on the 0.057-kg tennis ball by the player, = 661.2 N
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