During a test crash, an air bag inflates to stop a dummy’s forward motion. The dummy’s mass is 75 kg. If the net force on the dummy is 825 N toward the rear of the car, what is the dummy’s deceleration?
Answers
F = ma
825 = 75 a
a = 11 m/s²
The deceleration is 11 m/s²
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Answer:
The dummy's deceleration is eleven m/s².
Explanation:
From the above question,
They have given :
The dummy’s mass is 75 kg
The internet pressure appearing on the dummy is 825 N, and it is directed towards the rear of the car. According to Newton's 2d regulation of motion, the internet pressure on an object is equal to the mass of the object elevated by way of its acceleration:
net pressure = mass × acceleration
Rearranging this equation to resolve for acceleration, we get:
acceleration = internet pressure / mass
Plugging in the given values, we have :
acceleration = 825 N / seventy five kg
Simplifying this expression, we get:
acceleration = eleven m/s²
Therefore,
The dummy's deceleration is eleven m/s².
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