Question

During a test flight, a new aircraft flies 240 km south and then 140km
west. Find the distance of the aircraft from its starting point.
please answer and thanks!

Answer 1

Answer:

Apply Pythagorus theorem.

AC%5E2+=+AB%5E2+%2B+BC%5E2

or AC%5E2+=+285%5E2+%2B+320%5E2

or AC%5E2+=+81225+%2B+102400

or AC%5E2+=+183625

or AC+=+sqrt%28183625%29

or AC+=+428.515

Again, angle between AB and AC is

tan%28X%29+=+BC%2FAB

or tan%28x%29+=+320%2F285+=+1.1228

or X = tan inverse (1.1228) = 48.31%5Eo

So, the distance of the plane from its starting point is 428.515 km and the angle X is 48.31%

Answer 2

Answer:

since distance = the sum 9f the length of actual path

so , total distance from initial point to final point is = the sum of tolat distance traveled = 240km +140km =380km