Question

during a trip shyam walks a little faster than ram who started earlier ​

Answer 1

Ratio of speed of Shyam to Ram = (t1 + t2) / t2

Explanation:

Let Vs denote Vshyam and Vr denote Vram

Then dr = distance travelled by Ram in time t1

 dr` = distance travelled by Ram in time t2

 ds =  distance travelled by Shyam in time t2

In time t1, dr = Vr.t1

Shyam catches up with Ram in time t2.

Total distance travelled by Ram is the distance travelled by Shyam.

So dr + dr` = ds

 Vr.t1 + Vr.t2 = Vs.t2

   Vr (t1+t2) = Vs.t2

  Vs / Vr = (t1 + t2) / t2

Ratio of speed of Shyam to Ram = (t1 + t2) / t2

Answer 2

Answer:

Vshyam = 1/(t+ t1+t2)

Vram = 1/(t+t2)

Vs/Vr = when t is tending to zero

(t+t1+t2)^-1/(t+t2)^-1

= (t2)/(t1+t2)