Math, asked by Puppy7540, 1 year ago

During a war, a plane is sent to drop bombs on a bridge. The pilot knows that a direct hit is required to destroy the bridge. He also knows that each of his bombs has a probability of only 30% of scoring a direct hit. What is the minimum number of bombs he should drop so that his chances of successfully completing his mission are greater than 75%?

Answers

Answered by amitnrw
1

Given : a plane is sent to drop bombs on a bridge.   his bombs has a probability of only 30% of scoring a direct hit

To find : minimum number of bombs he should drop so that his chances of successfully completing his mission are greater than 75%

Solution:

Let say minimum number of Bomb dropped = n

Probability of direct hit p = 0.3

probability of not Direct hit q = 1 -0.3 = 0.7

P(x) = ⁿCₓpˣqⁿ⁻ˣ

successfully completing his mission are greater than 75%

=> Hitting 0 Direct hit <  25 %

=> P(0)  < 0.25

=> ⁿC₀(0.3)⁰(0.7)ⁿ  < 0.25

=> (0.7)ⁿ  < 0.25

Taking log both sides

=> n log (0.7)  < log (0.25)

=> n >   3.88

Hence n = 4

minimum number of bombs he should drop so that his chances of successfully completing his mission are greater than 75%  are 4

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