Question

during an adiabatic process the pressure of the gas is found to be proportional to 4th power of temperature the ideal gas would be​

Answer 1

Answer:

this answer will help you a lot

Answer 2

As per the question, we can say:

$P \propto {T}^{4}$

$\implies P {T}^{ - 4} = c \: \: \: \: ...(c = constant)$

• From ideal gas equation: PV = nRT, we replace value of T:

$\implies P {(PV)}^{ - 4} = c$

$\implies {P}^{ - 3} {V}^{ - 4} = c$

$\implies P {V}^{ \frac{4}{3} } = c$

• Since, this is an adiabatic process, we will compare with:

$\implies P {V}^{ \gamma } = c$

• So, value of $\gamma$ = 4/3.

So, ideal gas is a mixture of monoatomic and bi-atomic gases.