Question

during an experiment a signal from a specific reach to the ground station in 5 minutes what was the distance of spaceship from the ground station the signal​

Answer 1

Answer:

sol: Time taken, t= 5 minutes = 300 seconds

speed of signal, u = 3×10^8ms^-1

distance of spaceship

s = u×t

=3×10^8×300

=9×10^10 m.

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Answer 2

$\huge\star\sf\underline\pink{Solution :-}$

$\sf{We\:Know\:that ,} \\ \\ \\ {\boxed{\sf{ Speed = \dfrac{Distance\: travelled}{Time\:Taken} }}} \\ \\ \sf{Here,} \\ \\ \sf{Speed = 3 \times 10^8\:m/s} \\ \\ \sf{ Distance =? } \: \: \: \sf\purple{(To\:be\: calculated)} \\ \\ \sf{ Time\:Taken = 5\:min} \\ \\ \implies\sf{5 \times 60s} \\ \\ \implies\sf{300s} \\ \\ \sf{Now,} \\ \\ \sf\blue{Putting\:values\:of\:speed,} \\ \\ \\ {\sf{ 3 \times 10^8 = \dfrac{Distance\:travelled}{300} }} \\ \\ \sf{So,} \\ \\ \sf{ Distance\:Travelled = 3 \times 10^8 \times 300m} \\ \\ \implies\sf{9 \times 10^{10}\:m} \\ \\ \sf\green{Thus,} \\ \\ \sf\red{The\: Distance\:is\:9 \times 10^{10} \: Metres.}$