Question

During an experiment an ideal gas is found to obey an additional law VP^2=constant.
The gas is initially at a temperature T and volume V'When it expands to a volume
2V, the temperature becomes.​

Answer 1

Answer:

Final Temperature = Tf =(√2) T

Explanation:

According to question, VP^2 = K

Let Initiative volume and pressure is V and P respectively.

Let Vf and Pf final volume and pressure respectively.

Vf= 2V

V × P^2 = 2V × (Pf)^2

so, Pf = P/√2

Since, number of moles of gas is always constant in this case

so, (P×V)/(R×T) = (Pf×Vf)/(R×Tf)

now putting the value of Vf, Pf

P×V/RT =2V×P/√2/RTf

Tf = (√2) T