Physics, asked by malleshpbastipura, 8 months ago

During an expirement, a signal from a spaceship the ground station in five minutes what was the distance of the spaceship from the ground station? The signal travel at the speed of light, that is, 3×10(power)8m/s

Answers

Answered by shreyashkadam217
1

Answer:

Let the distance between the spaceship and the ground station be 'S' .

Then, S=vt

where, v= speed of signal =3×10

8

m/s

t= time taken =5min=5×60s=300s

∴s=3×10

8

×300=9×10

10

m

Explanation:

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Answered by khushiahire84
1

Answer:

the answer is.......

9×10^10

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