Question

During an isothermal process, 5.0 J of heat is removed from an ideal gas. What is the work done in the process?

Answer 1

$\huge\bf\red{*Answer*}$

When heat was removed from the ideal gas, work was done from outside and the ideal gas had performed negative work.

Now from 1st law of Thermodynamics,

∂Q=∂U+∂W

For an isothermal process

∂U=0

Given,

∂Q=−5J

So,

∂W=∂Q=−5J