During batting practice, two pop flies are hit from the same location, 2 s apart. The paths are modeled by the equations h = -16t2 + 56t and h = -16t2 + 156t - 248, where t is the time that has passed since the first ball was hit. Explain how to find the height at which the balls meet. Then find the height to the nearest tenth.
can some one hep pleas
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Answered by
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Both will meet at 40.5
Step-by-step explanation:
to find the height at which the balls meet.
first we will find the time at which they meet
h = -16t² + 56t
h = -16t² + 156t - 248
Equating both height to find time at which the balls meet
-16t² + 156t - 248 = -16t² + 56t
=> 100t = 248
=> t = 248/100
=> t = 62/25
height = -16t² + 56t
= - 16 (62/25)² + 56 *(62/25)
= (62/25²) ( - 16 * 62 + 56 * 25)
= (62/625) ( 408)
= 40.47
= 40.5
Both will meet at 40.5
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