Math, asked by flyboiimatthew, 9 months ago

During batting practice, two pop flies are hit from the same location, 2 s apart. The paths are modeled by the equations h = -16t2 + 56t and h = -16t2 + 156t - 248, where t is the time that has passed since the first ball was hit.

Explain how to find the height at which the balls meet. Then find the height to the nearest tenth.

Answers

Answered by amitnrw
0

Given : The paths are modeled by the equations h = -16t2 + 56t and h = -16t2 + 156t - 248, where t is the time that has passed since the first ball was hit.

To find : the height at which the balls meet.

Solution:

t is the time that has passed since the first ball was hit.

so at given time height should be same for balls to meet

Hence

Equating h = -16t² + 56t       & h = -16t² + 156t - 248

=> -16t² + 56t   = -16t² + 156t - 248

=> 100t  = 248

=> t  = 2.48

After 2.48 secs of first ball hit balls will meet

height = - 16(2.48)²  + 56(2.48)    or   -16(2.48)²  + 156(2.48) - 248

Height = 40.4736 ≈  40.5

Height at which balls meet  = 40.5  

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