Question

During electrolysis of water the volume of O2 liberated is
2.24 dm3. The volume of hydrogen liberated, under same conditions will be ~
[AIIMS 2008]
(a) 2.24 dm3
(b) 1.12 dm3
(c) 4.48 dm3
(d) 0.56 dm3​

Answer 1

(c) 4.48 dm^3 is the correct answer

Because, 2H2O -------> 2H2 + O2

There are 2 moles of H2 and same temp. and pressure.

Therefore, Volume of H2 - 2*2.24 = 4.48 dm^3

Answer 2

Answer:

hopefully the answer may be (d) 4.48 dm3

hope it helps you

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