Question

During electrolysis within 1 hour. 20 g of copper were released from the copper sulfate solution. what current flowed in the electrolyte? the electrochemical copper equivalent is 0.33 * 10–6

Answer 1

Answer:

i = 16.8 x 10³ A

Explanation:

Faraday's First law states that "The amount of substance (w) deposited or liberated or dissolved in an electrolysis chamber is directly proportional to the amount of current (charge(Q)) passed through the electrolytic chamber"

i.e w ∝ Q (but current i is rate of charge passes through a substance therefore Q=it)

w ∝ it

w = eit ( here e is called electrochemical equivalent )

here w = 20 g

        e=0.33 x 10^-6

        t= 1 hour = 3600 seconds

plug in all the values

20 =0.33 x 10 ^-6 x 3600 x i

i = 16.8 x 10³ A