Question

During free fall case of a lift, the Pseudo force acting on a body inside lift has magnitude​

Answer 1

Explanation:

Thus in the lift

When cable will be cut the the cond^n of weightlesness occurs

So, mg-N= ma

N=ma-mg

N=m(a-g)

Where (a = -g) bcz, a is acc^n and it is acting downwards.

So, N=m(g-g)

N=0

THUS , PSEUDO FORCE ACTING IS ALSO

ZERO(0).......

HOPE YOU MAY HAVE GOT IT.....

PLZ MARK IT AS BRAINLIEST