Question

During his travel to Dubai, Sam carries 75% of his money in traveler's checks and 25% in cash. At the
airport, he loses his entire cash and spends from his traveler's checks. On returning to India, he has
30% of the traveler's checks, which amounts to Rs. 18.000. What is the total money that he originally
carried?​

Answer 1

Answer: Rs. 80,000

Given that Sam had 75% of his money in traveler's checks and 25% in cash.

At the airport, he lost all his cash ( Which means he actually lost 25% of his money)

On returnig to India, he has 30% of his traveler's checks left which amounted to Rs. 18000

Let the total money he had be Rs. x.

According to the question,

Money in traveller's checks:

• 75% of total money

⇒ Initial money in traveller's checks = 75% of x

⇒ Money in Traveler's checks = 75/100 × x

⇒ Money in Traveler's checks = 0.75x

Now, On returning to India, He had 30% of his traveler's checks (30% of 0.75x) left which amounted to Rs. 18000.

⇒ 30% of 0.75x = 18000

⇒ 30/100 × 0.75x = 18000

⇒ 3 × 0.75x = 180000

⇒ 0.75x = 60000

⇒ x = 80000

Hence, Sam had originally carried a total money of Rs. 80,000 before going to Dubai.

Answer 2

Answer:

Sam had actually total money of Rs.80,000 before going to travel to Dubai.

Step-by-step explanation:

Consider that the total money Sam had is x.

Money Sam carries in cash = 25% of x

Money in traveler's check = 75% of x

                                           $=\frac{75}{100}*x$

                                           $=0.75x$

When Sam returned to India:

Sam had 30% of traveler's check = 30% of 0.75x =18000

⇒      $\frac{30}{100}*0.75x=18000$

⇒      $3*0.75x=180000$

⇒       $0.75x=60000$

∴          $x=80000$

Therefore the total money that Sam had before going to Dubai is equal to Rs.80000.