during hydrogenation of an alkene pressure of hydrogen gas pressure of hydrogen gas is decreased from 2atm to 1atm in 50 minutes. The rate of reaction would be
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Answer:
Rate of reaction=
timetaken
changeinpressure
=
75×60
2−1.1
atm/sec
=2×10
−4
atm/sec
so convert to mol/sec
Pv=nRT
V
n
=
RT
P
(
v
n
)/sec= molarity per second=
RT
P
/sec
since pressure/second is rate.
(
v
n
)/sec=
0.0821×300
2×10
−4
=8.12×10
−6
mol/sec
Thus, the rate of the reaction is 8.12×10
−6
mol/sec
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