during ionization of copper atom the quantum numbers of electron removed may be
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Copper have [Ar]3d104s1 electron configuration. And Zinc have [Ar]3d104s2 electron configuration.
My question is, what is the right quantum numbers of last electron of copper? Is it
a.n=3,l=2,m=+1,s=−1/2
or
b.n=3,l=2,m=+2,s=−1/2
If I use A, the electron configuration of copper is [Ar]3d94s2 and it isn't stable. But if I use B quantum numbers, it is the same with the last electron of zinc.
Explanation:
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