Question

DURING MEASUREMENT OF DENSITY OF CUBE 3℅ ERROR IS FOUND IN MEASURING MASS& 1℅ IN ITS LENGTH. THE MAXIMUM ℅ ERROR IN ITS DENSITY WILL BE....

Answer 1

Bonjour!

According to the question;

Percentage error in mass of cube = 3%

Percentage error in length of cube = 1%

As we know;

$= > density = \frac{mass}{volume } \\ \\ = > density = \frac{mass}{ {(length)}^{3} }$

So, maximum percentage error in density will be;

$= > \frac{ Δd}{d} \times 100 \% = \frac{Δm}{m} \times 100\% + 3 \frac{Δl}{l} \times 100\% \:$

$= > \frac{ Δd}{d} \times 100 \% =3\% + 3 \times 1\%$

$= > \frac{ Δd}{d} \times 100 \% = 3\% + 3\%$

$= >\frac{ Δd}{d} \times 100 \% = 6\%$

Maximum percentage error in density = 6%

Hope this helps...:)