Question

During n second of its motion a body covers a distance And with uniform acceleration 'a' and initial velocity 'u'. Show that, a=2Sn- 2u/2n-1

Answer 1

It is distance travelled in nth second.

Sn = u + 1/2a(2n-1)

Sn - u= 1/2a(2n-1)

2(Sn-u)/(2n-1) = a.

Hence proved.

By the way, if you are so derring-do where eq.1 came from then,

S1 be the distance travelled in (n-1) seconds

And S2 be the distance travelled in n seconds.

S2 - S1 is distance travelled in nth second Sn

S1 = u(n-1)-1/2a(n-1)^2

S2= un - 1/2an^2

S2-S1 = u - 1/2a(2n-1)

NOTE: the distance travelled in north seconds is different from distance travelled in nth second.

HOPE THIS HELPS.

Answer 2

Hope it helps.

Meri raah tujhi se, meri chaah tujhi se

Mujhe bas yahin reh jaana

Hai tu hi dil jaan hai, meri ab se

Na zikra tera na jaaye, mere lab se

Bulave tujhe yaar ajj meri galiyan

Basaun tere sang main alag duniyaa

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