During normal breathing, about 12% of the air in the lungs is replaced after one breath. Write an exponential decay model for the amount of the original air left in the lungs if the initial amount of air in the lungs is 500 mL. How much of the original air is present after 200 breaths? (Write in the form of equation.)
Please answer it fast because tomorrow exams are there.
Its urgent friends.
Answers
y=500(1-.12)^t=500(.88)^t
where t is the number of breaths
i.e y=500(.88)^200=0.000000004=4*10^-9 mL
#BAL #answerwithquality
after n breaths original air in lung = 500(0.88)ⁿ
Step-by-step explanation:
During normal breathing, about 12% of the air in the lungs is replaced after one breath
initial amount of air in the lungs is 500 mL.
After 1 breath original air in lung = 500 - (12/100)500
= 500*(88/100)
= 500 (0.88)
After 2 breath original air in lung = 500 (0.88) - (12/100)500 (0.88)
= 500 (0.88) (1 - 12/100)
= 500 (0.88) (0.88)
= 500(0.88)²
after n breaths original air in lung = 500(0.88)ⁿ
original air is present after 200 breaths = 500(0.88)²⁰
= 3.94 * 10⁻⁹ ml
= 3.94 pl (pico litre)
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