During normal breathing, about 12% of the air in the lungs is replaced after one breath. Write an equation that models the amount of the original air left in the lungs if the initial amount of air in the lungs is 500 ml and use it to determine how much of the original air is present after 240 breaths?
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Answer:
after breaths original air in lung = 500(0.88)ⁿ
Step-by-step explanation:
During normal breathing, about 12% of the air in the lungs is replaced after one breath
initial amount of air in the lungs is 500 mL.
After 1 breath original air in lung = 500 - (12/100)500
= 500*(88/100)
= 500 (0.88)
After 2 breath original air in lung = 500 (0.88) - (12/100)500 (0.88)
= 500 (0.88) (1 - 12/100)
= 500 (0.88) (0.88)
= 500(0.88)²
after n breaths original air in lung = 500(0.88)ⁿ
original air is present after 200 breaths = 500(0.88)²⁰
= 3.94 * 10⁻⁹ ml
= 3.94 pl (pico litre)
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