During our campaign against child labour we have found that in three glass making factories A, B and C there were total 33 children aged below 18 were involved. The ratio of male to female in A, B and C was 4 : 3, 3 : 2 and 5 : 4 respectively. If the no. of female children working in the factories B and C be equal, then find the no. of female children working in factory A?
Answers
Given:
Three glass-making factories A, B and C there were a total of 33 children aged below 18 were involved
The ratio of male to female in A, B and C was 4 : 3, 3 : 2 and 5 : 4 respectively
If the no. of female children working in the factories B and C be equal
To find:
The no. of female children working in factory A
Solution:
We have,
The number of male and female in factories A, B & C are:
Male Female
A: 4x 3x
B: 3y 2y
C: 5z 4z
Also given that,
No. of female children in B = No. of female children in C
⇒ 2y = 4z
⇒ y = 2z
Now,
Total no. of children in factories A, B & C = 33
⇒ [4x + 3x] + [3y + 2y] + [5z + 4z] = 33
⇒ [7x] + [3(2z) + 2(2z)] + [9z] = 33
⇒ 7x + 6z + 4z + 9z = 33
⇒ 7x + 19z = 33
the only value possible for z is 1
⇒ 7x + (19×1) = 33
⇒ 7x + 19 = 33
⇒ 7x = 33 - 19
⇒ 7x = 14
⇒ x = 2
∴ No. of female children working in factory A = 3x = 3 × 2 = 6
Thus, the no. of female children working in factory A is 6.
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