during respiration a six carbon molecule-glucose(c6h12o6) undergoes combustion calculate its molecular mass (atomic mass c= 12.0u, h =7.0u, o=16.0 u)
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molecular mass of C6= 12.0×6=72g
molecular mass of H12=7.0×12=84g
molecular mass of O6=16.0×6=96g
molecular mass of C6H12O6= 72g+84g+96g=252g
molecular mass of H12=7.0×12=84g
molecular mass of O6=16.0×6=96g
molecular mass of C6H12O6= 72g+84g+96g=252g
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