during respiration a six carbon molecule glucose (c6h12o6) undergoes combustion. calculate its molar mass
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Answered by
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180.15g/mol is the molar mass of c6h12o6
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3
6(12.011)+12(1.0079)+6(15.9994)=72.066+12.0948+95.9964=
180.157g/mol
180.157g/mol
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