English, asked by akhilviswa266, 3 months ago

during reverse bias a small current develops known as​

Answers

Answered by namrapatowarisl
0

Answer:

The small current developed during reverse bias is called reverse saturation current.

Explanation:

This small amount of current between p-n junction is developed when the diode is reversed. This current is of pico ampere order. This can be explained as the flow of minority carriers from the neutral region to the depletion region.

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Answered by aryansuts01
0

Answer:

Concept:

Inside a single crystal of semiconductor, a p–n junction is a border or interface among two made of semiconductor materials, p-type and n-type. In the outer shells of the electrically neutral atoms on the "p" side, there are more holes than electrons, while on the "n" side, there are more electrons. Only one channel of electrical current can pass through the junction as a result of this. The p-n junction is formed through doping, such as electrodeposition, dopant migration, or epitaxy. If two different pieces of material were employed, a grain boundary would form between the semiconductors, drastically limiting their utility by scattering electrons and holes.

Given:

A tiny current called as emerges during reverse bias.

Find:

find During reverse bias a small current develops known as​

Answer:

The answer is Reverse saturation current

When the diode is reverse biased, a tiny current of the order of a Pico ampere flows through the p-n junction. Reverse saturation current is the name given to this current. When the diode is inverted, a little amount of current flows between the p-n junction. The energy is in the tens of picoamperes. This can be explained by the movement of minority carriers from the neutral to depletion regions.

#SPJ2

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