Question

during the daytime temperature in the town was 30 degree Celsius. at night the temperature came down by 10 degree fahrenheit. what was the night time temperature in fahrenheit scale.... please solve completely ... in copy .....

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Answer 1

30°C = 86°F

Therefore, 86°F - 10°F = 76°F (Ans)

Answer 2

AnswEr:

$\begin{gathered}\begin{gathered}\frak{Given}\begin{cases} \sf{First\:Term\:(a)\:=\:17}\\ \sf{Last\:Term\:(L)\;=\; 350} \\ \sf{Common\: Difference\:(d)\:=\; 9}\end{cases}\end{gathered}\end{gathered}$

Given

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⎪

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FirstTerm(a)=17

LastTerm(L)=350

CommonDifference(d)=9

$\:\:\:\:\;\:\;\footnotesize\bold{\underline{\underline{\sf{\red{Formula\:For\:the\: Last\:Term\:is \:-}}}}}$

FormulaFortheLastTermis−

$\dag\;\:\large{\underline{\boxed{\sf{\purple{l\:=\; a +(n -1)d}}}}}$

l=a+(n−1)d

†

$\large\bold{\underline{\sf \green{Putting\:Values-}}}$

PuttingValues−

$:\implies\sf \: 350 = 17 + (n -1)9::⟹350=17+(n−1)9:$

$\implies\sf \:\cancel\dfrac{333}{9}$= (n -1)⟹

9

333

=(n−1)

$:\implies\sf \: (n -1)$ = 37:⟹(n−1)=37:⟹(n−1)=37:⟹(n−1)=37

:

$\implies\sf \: n$ = 37 + 1:⟹n=37+1⟹n=37+1:⟹n=37+1

$:\implies\large\boxed{\sf{\purple{n\:=\;38}}}$::⟹

n=38

:

$\small\bold{\underline{\sf{\pink{Therefore\:Given\:AP\: Contains\: 38\:Terms.}}}}$

ThereforeGivenAPContains38Terms.

$\large\bold{\underline{\sf{Now\: Finding\: Sum -}}}$ NowFindingSum−

$:\implies\sf \: S_{n}$ = \dfrac{n}{2} (a +l)::⟹S

$:\implies\sf \: S_{38}$ = $\dfrac{38}{2}(17 + 350):$⟹S

$:\implies\sf \: 19 \times 367::$⟹19×367:

$:\implies\large\boxed{\sf{\purple{6973}}}$::⟹

$\small\bold{\underline{\sf{\red{Sum \:of \: the \:Terms\: of \: the \: Given\: AP\; is \: 6973.}}}}$