. During the electrolysis of acidulated water,
the mass of hydrogen obtained is 'X' times
that of O, and the volume of H, is 'Y' times
that of O, The ratio of y' and 'X' is
1) 16 2) 8 3) 0.125 4) 0.25
Answers
The chemical reaction for electrolysis of water is given by:
2 H₂O ⇒ 2 H₂ + O₂
From the chemical equation, we can conclude:
2 moles of Hydrogen and 1 mole of oxygen is produced from 2 moles of water.
Thus mass of hydrogen obtained = mass of 2 moles of hydrogen
= 2 mole x 1 g/mole = 2 g
Mass of oxygen obtained = mass of 1 mole of oxygen
= 32 grams
According to question,
x = mass of hydrogen / mass of oxygen
= 2/32
= 1/16
Now, Volume of hydrogen obtained = 22.4 L/mole x 2 moles
= 44.8 L
Volume of oxygen obtained =22.4 L/mole x 1 mole
= 22.4
y = Volume of hydrogen/Volume of oxygen
= 44.8/22.4
= 2
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