Question

During the electrolysis of molten NaCl
solution, 230g of sodium metal is
deposited on the cathode, then how many
moles of chlorine will be obtained at anode
a) 10.0 b) 3.48 c) 35.5 d) 17.0lo

Answer 1

Explanation:

230g of Na means 10 moles of Na

so 10 moles of Cl- will be obtained

but it is released in the form of Cl2

so only 5 moles of Cl2 will be obtained

Answer 2

5 moles of chlorine will be obtained at anode

Explanation:

In the electrolysis of molten NaCl, sodium metal is deposited at the cathode which is a negative electrode and chlorine gas produces as the anode which is a positive electrode.

The two half-reaction equations are :

Reduction : $2Na^++2e^-\rightarrow 2Na$

Oxidation : $2Cl^-\rightarrow Cl_2+2e^-$

The overall equation is:

$2NaCl\rightarrow 2Na+Cl_2$

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

$\text{Number of moles of sodium}=\frac{230g}{23g/mol}=10moles$

For 2 moles of sodium , 1 mole of chlorine is produced

Thus for 10 moles of sodium = $\frac{1}{2}\times 10=5moles$ of chlorine is produced

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