Question

during the electrolysis of molten Nacl the time required to produce 0.10 mol of chlorine gas using a current of 3 ampere is

Answer 1

Answer:The time required to produce 0.10 mol of chlorine gas using a current of 3 ampere is 6433.3 seconds.

Explanation: $Q=I\times t$

where Q= quantity of electricity in coloumbs

I = current in amperes = 3 A

t= time in seconds = ?

$NaCl\rightarrow Na^++Cl^-$

$2Cl^{-}\rightarrow Cl_2+2e^{-1}$

1 mole of electrons carry charge= 96500 C.

$96500\times 2=193000Coloumb$ of electricity deposits 1 mole of $Cl_2$

1 mole of $Cl_2$ is deposited by 193000 C

Thus 0.10 moles of  $Cl_2$ is deposited by=$\frac{193000}{1}\times 0.10=19300C$

$19300C=3A\times t$

$t=6433.3 sec$

Answer 2

Answer:

Explanation:

Explanation : During the electrolysis of molten sodium chloride, According to Faraday's first law of electrolysis, w = Z x I x t

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