Question

During the emission spectrum the first line of lyman series of H atom occurs as lambda=x the wavelength of the 1 st line of lyman series of he+
A.X/4
B.3X
C.3/X
D.4X

Answer 1

I think it will 4x means option no. D

Answer 2

heya.........

#....There is a direct relation in which the wavelength is directly proportional to the square of the no. of shell in which it is present(n), so for lyman series n=1 wavelength is given which is lambda

For lyman series n=1

As wavelength is directly proportional to square of 'n' so, let us assume wavelength of lyman series to be equal to 'x'

Lambda/x = 1×1/2×2

4(lambda) = x.

lambda=x/4

tysm...........#kundan