Question

During the formation of ammonia, what mass of hydrogen gas would be required to react completely with 42 g of nitrogen gas?

Answer 1

Explanation:

Molecular mass of ammonia NH3 = mass of N + mass of H = 14 + 3 × 1 =17 To react with 14 g N mass of H required = 3 g Therefore to react with 42 g N mass of H required = 3/ 14 ×42 = 9g. Hydrogen and oxygen combine in the ratio of 1:8 by mass to form water.

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