Question

During the head on collision of two masses 1 kg and 2 kg the maximum energy of deformation is 100/3J. If before collision the masses are moving in the opposite direction, then their velocity of approach before the collision is: J ??​

Answer 1

Answer:

1

μV

ret

2

=energystored=

3

100

2

1

×

3

2

×v

ret

2

=

3

100

v

ret

=10m/s

Momentum conserve,

1.v

1

−2V

2

=0

v

1

=2V

2

V

1

−(V

2

)=10

V

1

+V

2

=10

velocity of approach=10m/s

Explanation:

hope this helps uh ✌

gm ^_^

Answer 2

Answer:

this is the correct answer of this question

Explanation:

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