History, asked by abndsasikumar, 17 days ago

During the middle ages, Europe made remarkable progress in education. The expansion

of basic education, universities, Greco-Roman knowledge and Islamic knowledge were

the features of the Medieval Age. Complete the table based on this.

Progress in the field of trade and culture in the medieval world led to the beginning of the

modern age. Do you agree with this statement? Substantiate your arguments.

I

The main subjects

offered in Gurukula

system in India.

• Languages





The major subjects

taught in the medieval

schools.

• Grammar





The main subjects taught

in universities

• Philosophy





Medieval Education​

Answers

Answered by kelly324141
1

Answer:

Equações D

iferenciais de Primeir

a Ordem Exatas

(y + 2xy³) dx + (1 + 3x²y² + x) dy = 0

Answered by Anonymous
1

Correct Question :-

Prove that :- \mathsf{\;\dfrac{1 - cos\theta}{1 + cos\theta}}=\mathsf{(cosec\theta - cot\theta)^2}

To Prove :-

\mathsf{\;\dfrac{1 - cos\theta}{1 + cos\theta}}=\mathsf{(cosec\theta - cot\theta)^2}

Proof :-

\mathsf\pink{{ \:  \:  \:  \:   \:  \:  \:  \:  \: \:\:L.H.S :\;\dfrac{1 - cos\theta}{1 + cos\theta}}}\\

\mathsf{ \:  \:  \:  \:   \:  \:  \:  \:  \: \:\::\implies \dfrac{(1 - cos\theta)(1 - cos\theta)}{(1 + cos\theta)(1 - cos\theta)}}\\

 We know that : (a + b)(a - b) = a² - b²

\mathsf{ \:  \:  \:  \:   \:  \:  \:  \:  \: \:\::\implies (1 - cos\theta)(1 + cos\theta) = 1 - cos^2\theta}\\

\mathsf{ \:  \:  \:  \:   \:  \:  \:  \:  \: \:\::\implies \dfrac{(1 - cos\theta)^2}{1 - cos^2\theta}}\\

\bigstar\;\;\textsf{We know that : \boxed{\mathsf{1 - cos^2\theta = sin^2\theta}}}

\mathsf{ \:  \:  \:  \:   \:  \:  \:  \:  \: \:\::\implies \dfrac{(1 - cos\theta)^2}{sin^2\theta}}\\

\mathsf{ \:  \:  \:  \:   \:  \:  \:  \:  \: \:\::\implies \bigg[\dfrac{1 - cos\theta}{sin\theta}\bigg]^2}\\

\mathsf{ \:  \:  \:  \:   \:  \:  \:  \:  \: \:\::\implies \bigg[\dfrac{1}{sin\theta} - \dfrac{cos\theta}{sin\theta}\bigg]^2}\\

We know that :

\;\;\boxed{\mathsf{\dfrac{1}{sin\theta} = cosec\theta}}\\

\;\;\boxed{\mathsf{\dfrac{cos\theta}{sin\theta} = cot\theta}}\\

\mathsf\pink{{ \:  \:  \:  \:   \:  \:  \:  \:  \: \:\::\implies (cosec\theta - cot\theta)^2}}\\

Hence (Proved..!)

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