Question

During the nth second of its motion a body covers a distance Sn with uniform acceleration a and initial velocity u. Show that a=2Sn-2u/2n-1

Answer 1

Answer:

Let the total time of motion be t then u =initial velocity, and a =acceleration

distance travelled in in t seconds will be

Dt = u t + ½ a t^2

D(t-1) = u(t – 1) + ½ a (t-1)^2

distance travelled in 1 sec less from total time

Distance travelled in nth sec = Sn = Dt – Dt-1 = u + ½ a (2t – 1)

thus

a = 2(Sn – u) / 2n – 1

Step-by-step explanation:

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