Physics, asked by unknown1505, 9 months ago

. During the rocket propulsion, gases are ejecting with
velocity 1 km/s relative to rocket. The rate of fuel
consumption is m /10 kg/s, where m is the instantaneous
mass of the rocket. If air resistance varies according
to equation f = 0.15 mv, then terminal velocity of the
rocket is:
(AIIMS, 2015]
(A) 300 m/s
(B) 600 m/s
(C) 7.92 km/s (D) 11.2 km/s​

Answers

Answered by jairajrajawat32
4

Answer:

600m/sec

Explanation:

vdm/dt=mg +f

1000(m/10) =10m+0.15mv

v=600

Enjoy

Similar questions