Question

during the sprint of hundred metre the maximum speed acquired by athlete was 10 metre per second if its acceleration is uniform then its speed when he was at the middle of the run is what​

Answer 1

definitely, initial velocity of athlete , u = 0

and final velocity of him, v = 10 m/s

displacement, s = 100m

using formula, v² = u² + 2as

⇒(10)² = 0² + 2a(100)

⇒a = 0.5 m/s²

hence, uniform acceleration of athlete is 0.5 m/s².

now, speed of athlete at middle , v'

v'² = u² + 2a(s/2)

⇒v'² = 0² + 2(0.5)(100/2)

⇒v'² = 50

⇒v' = 5√2 m/s [ans]

Answer 2

Answer:

Explanation:

Given :-

Initial velocity of Athlete , u = 0

Final velocity of Men, v = 10 m/s

Displacement, s = 100m

To Find :-

Final speed when he was at the middle.

Formula to be used :-

v² = u² + 2as

Solution :-

Putting all the values, we get

v² = u² + 2as

⇒ (10)² = 0² + 2a(100)

⇒ a = 0.5 m/s²

Now, speed of athlete at middle , v'

⇒ v² = u² + 2as

⇒ v'² = u² + 2a(s/2)

⇒ v'² = 0² + 2(0.5)(100/2)

⇒ v'² = 50

⇒ v' =  5√2 m/s

Hence, Final speed when he was at the middle is 5√2 m/s.