Math, asked by s9064587, 11 months ago

During the week of a convention, there were 60,000 occupied hotel rooms and 20,000 unoccupied hotel rooms in Grayson's city. What percentage of the hotel rooms in the city were occupied during the convention? Write your answer using a percent sign (%).

Answers

Answered by pixx
1

Answer:

20000/60000*100

1/3*100

100/3 = 33.33%

Answered by sankalpjhamb10
1

Answer:

75%

Step-by-step explanation:

60,000 occupied rooms

20,000 unoccupied

total = 60,000 + 20,000 = 80,000

Percentage occupied  =  \frac{60000}{80000}  * 100  = 150/2 = 75%

Therefore, 75% of hotel rooms in the city were occupied during the convention.

Similar questions