Question

durng 3 years, 2017, 2018 and 2019, a batsman scored 900, 1209 and 1044 nus at averages of 45, 46.5 and
43.5, respectively. What was his average (correct up to two decimal places) for the period of the mentioned 3 years​

Answer 1

Answer:

Mean of average = Sum of the observations /Number of observations

Step-by-step explanation:

45+46.5+43.5/3

155.0/3

51.66 is his average for the period of mentioned 3 years

Answer 2

For year 2017,

Runs scored = 900

Average = 45

=> total number of runs / number of times they have been out = 45

=> $\frac{900}{n_{1} }= 45$

=> $n_{1} = \frac{900}{45}$

=> $n_{1}= 20$

For year 2018,

Runs scored = 1209

Average = 46.5

=> total number of runs / number of times they have been out = 46.5

=> $\frac{1209}{n_{2} }= 46.5$

=> $n_{2}= 26$

For year 2019,

Runs scored = 1044

Average = 43.5

=> total number of runs / number of times they have been out = 43.5

=> $\frac{1044}{n_{3} }= 43.5$

=> $n_{3}= 24$

Average for three years would be

Average = total runs scored / $n_{1} + n_{2} + n_{3}$

=> Average  =  $\frac{900+1209+1044}{n_{1} + n_{2} + n_{3}}$

                    = $\frac{3153}{70}$

                    = 45.04

Therefore, Average of batsman for the period of three years is 45.04.